Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 5 - Section 5.1 - Energy and Energy Changes - Checkpoint: 5.1.4

Answer

e) 9.00$\times10^{5}$ J.

Work Step by Step

215 Cal= $215 Cal\times\frac{4184J}{1 Cal}= 9.00\times10^{5} J$.
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