Answer
a) 7.20 mL
Work Step by Step
H₂SO₄ (aq) + Ba(OH)₂ (aq) → BaSO₄ (s)+ 2H₂O (l)
From the balanced equation, we notice that 1 mmol of Ba(OH)₂ is neutralized with 1 mmol of H₂SO₄ , as the reaction ratio is 1:1 .
we have, n (mmol) = M(mo/L)×L(mL)
→ n (mmol) of neutralized of Ba(OH)₂ = 0.0415 × 25 = 1.0375 mmol
and n (mmol) of H₂SO₄ = 1.0375 mmol
So, L (mL) = n (mmol/L) / M (mol/L) = 1.0375/0.144 = 7.20 mL
