## Chemistry (4th Edition)

The pH of a pure water solution at 37 $^{\circ}$ is 6.801.
1. Find $pK_w$: $pK_w = -log(K_w) = -log(2.5 \times 10^{-14})$ $pK_w \approx 13.602$ 2. Pure water = Neutral, therefore: $pH = pOH$ Create a unknown, called "x", where: x = pH = pOH. Therefore, using the equation: pH + pOH = pKw x + x = pKw 2x = 13.602 x = $\frac{13.602}{2}$ = 6.801 So, the pH (and the pOH) of a pure water solution at 37 $^{\circ}$ is 6.801.