## Chemistry (4th Edition)

For strong acids: $[Acid] = [H_3O^+]$. - $HI, HClO_4$ and $HCl$ are strong acids. (a) $pH = -log[H_3O^+]$ $pH = -log( 1.02)$ $pH = 0.0086$ (b) $pH = -log[H_3O^+]$ $pH = -log( 3.5 \times 10^{- 2})$ $pH = 1.45$ (c) $pH = -log[H_3O^+]$ $pH = -log( 1.5 \times 10^{- 6})$ $pH = 5.82$