Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 15 - Questions and Problems - Page 708: 15.24

Answer

$5.1\times10^{-2}$

Work Step by Step

$K_{p} = \frac{(P_{NO})^{2}}{(P_{N_{2}}) (P_{O_{2}})} = \frac{(0.050atm)^{2}}{0.15atm\times 0.33atm} \approx 5.1\times 10^{-2}$
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