## Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company

# Chapter 15 - Questions and Problems - Page 708: 15.21

#### Answer

$2.40\times10^{33}$

#### Work Step by Step

If we reverse an equation, the equilibrium constant becomes the reciprocal of the original $K_{c}$. Then equilibrium constant for the new equation=$\frac{1}{K_{c}} =\frac{1}{4.17\times10^{-34}} = 2.40\times10^{33}$

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