Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 17 - Entropy, Free Energy, and Equilibrium - Questions & Problems - Page 805: 17.18

Answer

a)-1139.2 kJ/mol b) -140.0 kJ/mol c) -2935.02 kJ/mol

Work Step by Step

We find: $a)2(-569.6)-0-2(0)= -1139.2$ $b)2(-370.4)-2(-300.4)-0=-140$ $c)6(-237.2)+4(0394.4)-2(-32.89)=-2935.02$
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