Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 17 - Entropy, Free Energy, and Equilibrium - Questions & Problems: 17.25

Answer

Please see the work below.

Work Step by Step

We know that $\Delta G^{\circ}=RTlnK$ We plug in the known values to obtain: $\Delta G^{\circ}=8.314\times 298\times ln(1.16\times 10^{-14})=79KJ$
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