Answer
As the electronegativity difference between bonded atoms increases, the polarity of the bonds increases, and as a result, the dipole moment of the molecules increases. The dipole moment of $CBr_{4}$ and $CO_{2}$ is zero. The electronegativity difference of the molecules increases as follows:
$H_{2}S < NH_{3} < H_{2}O < HF$
Therefore, increasing order of dipole moment is:
$CBr_{4} = CO_{2} < H_{2}S < NH_{3} < H_{2}O < HF$
Work Step by Step
As the electronegativity difference between bonded atoms increases, the polarity of the bonds increases, and as a result, the dipole moment of the molecules increases. The dipole moment of $CBr_{4}$ and $CO_{2}$ is zero. The electronegativity difference of the molecules increases as follows:
$H_{2}S < NH_{3} < H_{2}O < HF$
Therefore, increasing order of dipole moment is:
$CBr_{4} = CO_{2} < H_{2}S < NH_{3} < H_{2}O < HF$
