Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Measurements and Calculations - Page 38: 46

Answer

$1.65 \frac{g}{cm^3}$

Work Step by Step

$6.080 mg= .00608 g$ $2.2 mm \times 1.36mm \times 1.23 mm = 3.68 mm = .0036 cm^3$ $.00608 g \div .00368 cm^3=1.65 \frac{g}{cm^3}$
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