Chemistry 10th Edition

Published by Brooks/Cole Publishing Co.
ISBN 10: 1133610668
ISBN 13: 978-1-13361-066-3

Chapter 1 - The Foundations of Chemistry - Exercises - Measurements and Calculations - Page 38: 37


5.31 cm= 5.31$\times10^{-2}$ m 5.31 cm= 5.31$\times10^{-2}\times10^{3}$ millimeters=5.31$\times10^{1}$ millimeters. 5.31 cm= 5.31$\times10^{-2}\times10^{-3}$ kilometers= 5.31$\times10^{-5}$ km. 5.31 cm=5.31$\times10^{-2}\times10^{6}$ micrometers= $5.31\times10^{4}$ micrometers

Work Step by Step

To solve the above problem we want to know the values of prefixes. kilo=1000, micro=$10^{-6}$ , milli=$10^{-3}$ and centi=$10^{-2}$. We substitute these values carefully. For more complex problems we can use unit factor method.
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