# Chapter 1 - The Foundations of Chemistry - Exercises - Measurements and Calculations - Page 38: 36

(a) 0.4534 km (b) 36300 m (c) 487000 g (d) 1320 mL (e) 5.59 dL (f) 6.251 $\times 10^6 \space cm^3$

#### Work Step by Step

(a) $$453.4 \space m \times \frac{10^{-3} \space km}{1 \space m} = 0.4534 \space km$$ (b) $$36.3 \space km \times \frac{1 \space m}{10^{-3} \space km} = 36300 \space m$$ (c) $$487 \space kg \times \frac{1 \space g}{10^{-3} \space kg} = 487000 \space g$$ (d) $$1.32 \space L \times \frac{1 \space mL}{10^{-3} \space L} = 1320 \space mL$$ (e) $$55.9 \space dL = 55.9 \space (10^{-1})L = 5.59 \space L$$ (f) $$6251 \space L \times \frac{1 \space cm^3}{10^{-3} \space L} = 6.251 \times 10^6 \space cm^3$$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.