Chapter 1 - The Foundations of Chemistry - Exercises - Measurements and Calculations - Page 38: 48

a) $42.2\, cm^{3}$ b) $3.48\, cm$ c) $1.37\, in$

a) $\text{Volume}=\frac{\text{Mass}}{\text{Density}}=\frac{0.443\times10^{3}\,g}{10.5\,g/cm^{3}}$ $=42.2\,cm^{3}$ b) $\text{Volume}= (\text{Edge length}) ^{3}$ $\implies \text{Edge length}=\sqrt[3] {\text {Volume}}$ $=\sqrt[3] {42.2\, cm^{3}}=3.48\,cm$ c) $\text{Edge length}=3.48\, cm=3.48\, cm\times\frac{1\,in}{2.54\,cm}$ $=1.37\,in$