Answer
$\cos(-\theta)\csc(-\theta)\tan(-\theta)=1$
Work Step by Step
$\csc(-\theta)$ can be written as $\frac{1}{\sin(-\theta)}$.
$\tan(-\theta)$ can also be written as $\frac{\sin(-\theta)}{\cos(-\theta)}$.
Therefore, the equation can be rewritten:
$\cos(-\theta)\csc(-\theta)\tan(-\theta)=\cos(-\theta)\frac{1}{\sin(-\theta)}\frac{\sin(-\theta)}{\cos(-\theta)}=1$
As the trigonometric terms cancel out,
$\cos(-\theta)\csc(-\theta)\tan(-\theta)=1$
