Answer
$\sin(-\theta)\cot(-\theta)=\cos(\theta)$
Work Step by Step
$\cot(\theta)$ is the reciprocal of $\tan(\theta)$, and is $\frac{1}{\tan(\theta)}$.
Since $\tan(\theta)$ is also $\frac{\sin(\theta)}{\cos(\theta)}$, $\cot(-\theta)=\frac{\cos(-\theta)}{\sin(-\theta)}$.
Therefore,
$\sin(-\theta)\cot(-\theta)=\sin(-\theta)\frac{\cos(-\theta)}{\sin(-\theta)}=\cos(-\theta)$
Since cosine is an even function,
$\cos(-\theta)=\cos(\theta)$
