Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 4 - Section 4.1 - Basic Graphs - 4.1 Problem Set - Page 192: 44

Answer

$\frac{\sqrt 2}{2}$

Work Step by Step

Since sine is an odd function, $\sin(-\frac{7\pi}{4})=-\sin(\frac{7\pi}{4})$ Using the unit circle, $\frac{7\pi}{4}$ is in the fourth quadrant, where sine is negative. Using the identity $\sin(2\pi-\theta)=-\sin(\theta)$, $-\sin(\frac{7\pi}{4})=-\sin(2\pi-\frac{\pi}{4})=\sin(\frac{\pi}{4})$ $\frac{\pi}{4}$ is a special angle, $\sin(\frac{\pi}{4})=\frac{\sqrt 2}{2}$ Therefore, $\sin(-\frac{7\pi}{4})=\frac{\sqrt 2}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.