Answer
$\sin(-\theta)\sec(-\theta)\cot(-\theta)=1$
Work Step by Step
$\sec(-\theta)$ can be written as $\frac{1}{\cos(-\theta)}$
$\cot(-\theta)$ can also be written as $\frac{\cos(-\theta)}{\sin(-\theta)}$.
As such,
$\sin(-\theta)\sec(-\theta)\cot(-\theta)=\sin(-\theta)\frac{1}{\cos(-\theta)}\frac{\cos(-\theta)}{\sin(-\theta)}=1$.
The trigonometric terms in the equation cancel out, therefore,
$\sin(-\theta)\sec(-\theta)\cot(-\theta)=1$.
