Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.5 - Velocities - 3.5 Problem Set - Page 164: 9

Answer

15 mi/hr

Work Step by Step

We know that if point $P$ is a point on a circle of radius $r$, and $P$ moves in a distance $s$ on the circumference of the circle in an amount of time $t$, then the linear velocity, $v$, of $P$ is calculated as $v=\frac{s}{t}$. We are given that $s=30$ mi and $t=2$ hr. Therefore, $v=\frac{30mi}{2hr}=\frac{30mi\div2}{2hr\div2}=\frac{15mi}{1hr}=15$ mi/hr.
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