## Trigonometry 7th Edition

If $P$ is a point moving with uniform circular motion on a circle of radius $r$, and the line from the center of the circle through $P$ sweeps out a central angle $\theta$􏰂 in an amount of time $t$, then the angular velocity, $\omega$ 􏰌 (omega), of $P$ is calculated as $\omega=\frac{\theta}{t}$. We are given that $\theta=12$ radians and $t=3$ min. Therefore, $\omega=\frac{12radians}{3min}=\frac{12radians\div3}{3min\div3}=\frac{4radians}{1min}=4$ radians/min.