Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.5 - Velocities - 3.5 Problem Set - Page 164: 21


117.81 radians/hr

Work Step by Step

If $P$ is a point moving with uniform circular motion on a circle of radius $r$, and the line from the center of the circle through $P$ sweeps out a central angle $\theta$􏰂 in an amount of time $t$, then the angular velocity, $\omega$ 􏰌 (omega), of $P$ is calculated as $\omega=\frac{\theta}{t}$. We are given that $\theta=45\pi$ radians and $t=1.2$ hr. Therefore, $\omega=\frac{45\pi radians}{1.2 hr}\approx117.81$ radians/hr.
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