Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.5 - Velocities - 3.5 Problem Set - Page 164: 6

Answer

5 ft/min

Work Step by Step

We know that if point $P$ is a point on a circle of radius $r$, and $P$ moves in a distance $s$ on the circumference of the circle in an amount of time $t$, then the linear velocity, $v$, of $P$ is calculated as $v=\frac{s}{t}$. We are given that $s=10$ ft and $t=2$ min. Therefore, $v=\frac{10ft}{2min}=\frac{10ft\div2}{2min\div2}=\frac{5ft}{1min}=5$ ft/min.
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