Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Test - Page 111: 9

Answer

$\dfrac{1}{2}$

Work Step by Step

$30^o$ is a special angle whose sine value is $\dfrac{1}{2}$. RECALL: $\csc{\theta} = \dfrac{1}{\sin{\theta}}$ Thus, $\dfrac{1}{\csc{30^o}} \\=\dfrac{1}{\frac{1}{\sin{30^o}}} \\=1 \cdot \dfrac{\sin{30^o}}{1} \\=\sin{30^o} \\=\dfrac{1}{2}$
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