## Trigonometry 7th Edition

$\dfrac{1}{2}$
$30^o$ is a special angle whose sine value is $\dfrac{1}{2}$. RECALL: $\csc{\theta} = \dfrac{1}{\sin{\theta}}$ Thus, $\dfrac{1}{\csc{30^o}} \\=\dfrac{1}{\frac{1}{\sin{30^o}}} \\=1 \cdot \dfrac{\sin{30^o}}{1} \\=\sin{30^o} \\=\dfrac{1}{2}$