Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Test - Page 111: 10

Answer

$73^o10'$

Work Step by Step

Add the corresponding parts to obtain: $=(48+24)^o + (18+52)' \\=72^o + 70'$ RECALL: $60' = 1^o$ Use the conversion above to obtain $72^o+70' \\=72^o + 60' + 10' \\=72^o + 1^o + 10' \\=73^o+10' \\=73^o10'$
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