Answer
$\tan{71^o20'}= 0.337833023 \approx 0.3378$
Work Step by Step
RECALL:
$\cot{\theta} = \dfrac{1}{\tan{\theta}}$
Use a calculator to evaluate the given expression and have:
$\tan{71^o20'}= \dfrac{1}{\cot{71^o20'}} = 0.337833023 \approx 0.3378$
