Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Test - Page 111: 11

Answer

$73^o12'$

Work Step by Step

RECALL: $1^o=60'$ Use the conversion rate above to obtain: $\require{cancel} 73.2^0 \\= 73^0 + 0.2^o \\=73^o + 0.2^o \cdot \left(\dfrac{60'}{1^o}\right) \\=73^o + 0.2^\cancel{o} \cdot \left(\dfrac{60'}{1^\cancel{o}}\right) \\=73^o + 0.2(60') \\=73^o + 12' \\=73^o12'$
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