Answer
(a) We can see the graph below.
(b) $x = y^4$
Work Step by Step
$x = t^2$
$y = \sqrt{t}$
(a)
t = 0:
$x = (0)^2 = 0$
$y = \sqrt{0} = 0$
t = 1:
$x = (1)^2 = 1$
$y = \sqrt{1} = 1$
t = 2
$x = (2)^2 = 4$
$y = \sqrt{2}$
t = 3
$x = (3)^2 = 9$
$y = \sqrt{3}$
t = 4:
$x = (4)^2 = 16$
$y = \sqrt{4} = 2$
We can see the graph below.
(b)
$y = \sqrt{t}$
$t = y^2$
$x = t^2$
$x = (y^2)^2$
$x = y^4$