Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.6 Parametric Equations, Graphs, and Applications - 8.6 Exercises - Page 398: 6

(a) We can see the graph below. (b) $x = 2y-2$

$x = 2t$ $y = t+1$ (a) t = -2: $x = 2(-2) = -4$ $y = (-2)+1 = -1$ t = -1: $x = 2(-1) = -2$ $y = (-1)+1 = 0$ t = 0: $x = 2(0) = 0$ $y = (0)+1 = 1$ t = 1: $x = 2(1) = 2$ $y = (1)+1 = 2$ t = 2: $x = 2(2) = 4$ $y = (2)+1 = 3$ t = 3: $x = 2(3) = 6$ $y = (3)+1 = 4$ We can see the graph below. (b) $y = t+1$ $t = y-1$ $x = 2t$ $x = 2(y-1)$ $x = 2y-2$