Answer
-1
Work Step by Step
We know that $i^{2}=-1$. Therefore, $i^{4}=i^{2}\times i^{2}=-1\times-1=1$.
We can use the fact that $i^{4}=1$ in order to evaluate higher powers of $i$.
$i^{22}=i^{20}\times i^{2}=(i^{4})^{5}\times i^{2}=(1)^{5}\times-1=1\times -1=-1$