Answer
$0+8i$
Work Step by Step
$\frac{8}{-i}=\frac{8}{-i}(\frac{i}{i})=\frac{8\times i}{-i\times i}=\frac{8i}{-i^{2}}=\frac{8i}{-(-1)}=\frac{8i}{1}=8i=0+8i$
We know that $i^{2}=-1$.
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 358: 89
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