Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 358: 88

Answer

$0+6i$

Work Step by Step

$\frac{-6}{i}=\frac{-6}{i}(\frac{-i}{-i})=\frac{-6\times-i}{i\times-i}=\frac{6i}{-i^{2}}=\frac{6i}{-(-1)}=\frac{6i}{1}=6i=0+6i$ We know that $i^{2}=-1$.
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