Answer
$0+6i$
Work Step by Step
$\frac{-6}{i}=\frac{-6}{i}(\frac{-i}{-i})=\frac{-6\times-i}{i\times-i}=\frac{6i}{-i^{2}}=\frac{6i}{-(-1)}=\frac{6i}{1}=6i=0+6i$
We know that $i^{2}=-1$.
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