Answer
$0-\frac{5}{9}i$
Work Step by Step
$\frac{5}{9i}=\frac{5}{9i}(\frac{-i}{-i})=\frac{5\times -i}{9i\times -i}=\frac{-5i}{-9i^{2}}=\frac{-5i}{-9(-1)}=\frac{-5i}{9}=-\frac{5}{9}i=0-\frac{5}{9}i$
We know that $i^{2}=-1$.
Trigonometry (10th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
0321671775
ISBN 13:
978-0-32167-177-6
Chapter 8 - Complex Numbers, Polar Equations, and Parametric Equations - Section 8.1 Complex Numbers - 8.1 Exercises - Page 358: 92
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