Answer
$(sec~\theta+tan~\theta)(1-sin~\theta) = cos~\theta$
Work Step by Step
We can see that the graph looks like $y = cos~\theta$.
We can verify this algebraically.
$(sec~\theta+tan~\theta)(1-sin~\theta)$
$= (\frac{1}{cos~\theta}+\frac{sin~\theta}{cos~\theta})(1-sin~\theta)$
$= (\frac{1+sin~\theta}{cos~\theta})(1-sin~\theta)$
$= \frac{1-sin^2~\theta}{cos~\theta}$
$= \frac{cos^2~\theta}{cos~\theta}$
$= cos~\theta$
