Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.3 The Unit Circle and Circular Functions - 3.3 Exercises - Page 117: 6

Answer

(a) $\sin{(-\frac{3\pi}{2})}=1$ (b) $\cos{(-\frac{3\pi}{2})}=0$ (c) $\tan{(-\frac{3\pi}{2})} \text{ is undefined}$

Work Step by Step

RECALL: $\sin{s} = y \\\cos{s} = x \\\tan{s} = \frac{y}{x}$ The angle $-\dfrac{3\pi}{2}$ ($\frac{3\pi}{2}$ degrees clockwise) will intersect the unit circle at the point $(0, 1)$ (refer to Figure 15 on page 113). The point $(0, 1)$ has: $x=0 \\y=1$ Thus, $\sin{(-\frac{3\pi}{2})}=1 \\\cos{(-\frac{3\pi}{2})}=0 \\\tan{(-\frac{3\pi}{2})}=\frac{1}{0} \text{ (undefined)}$
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