Trigonometry (10th Edition)

Published by Pearson
ISBN 10: 0321671775
ISBN 13: 978-0-32167-177-6

Chapter 3 - Radian Measure and the Unit Circle - Section 3.3 The Unit Circle and Circular Functions - 3.3 Exercises - Page 117: 2

Answer

(a) $\sin{\pi}=0$ (b) $\cos{\pi}=-1$ (c) $\tan{\pi}= 0$

Work Step by Step

RECALL: $\sin{s} = y \\\cos{s} = x \\\tan{s} = \frac{y}{x}$ The angle $\pi$ will intersect the unit circle at the point $(-1, 0)$ (refer to Figure 15 on page 113). The point $(-1, 0)$ has: $x=-1 \\y=0$ Thus, $\sin{\pi}=0 \\\cos{\pi}=-1 \\\tan{\pi}=\frac{0}{-1} = 0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.