## Trigonometry (11th Edition) Clone

Published by Pearson

# Chapter 8 - Test - Page 412: 9a

#### Answer

Two pairs of polar coordinates for this point are: $(5, 90^{\circ})$ $(-5, 270^{\circ})$

#### Work Step by Step

$(0,5)$ $r = \sqrt{0^2+5^2} = 5$ Since the point is on the positive y-axis, $\theta = 90^{\circ}$ Two pairs of polar coordinates for this point are: $(5, 90^{\circ})$ $(-5, 270^{\circ})$

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