Answer
Two pairs of polar coordinates for this point are:
$(5, 90^{\circ})$
$(-5, 270^{\circ})$
Work Step by Step
$(0,5)$
$r = \sqrt{0^2+5^2} = 5$
Since the point is on the positive y-axis, $\theta = 90^{\circ}$
Two pairs of polar coordinates for this point are:
$(5, 90^{\circ})$
$(-5, 270^{\circ})$
