Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 8 - Test - Page 412: 3a



Work Step by Step

Step 1: $i^{15}=i^{14+1}=i^{14}\times i$=$(i^{2})^{7}\times i$ Step 2: As $i^{2}=-1$, $(i^{2})^{7}\times i=(-1)^{7}\times i=-1\times i=-i$
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