#### Answer

Since -3 + 4i satisfies the equation $x^2+6x+25=0$, it is a solution of the equation.

#### Work Step by Step

For -3 + 4i to be a solution of the equation $x^2+6x+25=0$,
-3 + 4i should satisfy the equation.
Substitute $x=−3+4i$ into $x^2+6x+25$, we have
$(−3+4i)^2+6(−3+4i)+25$
= $9−24i+16i^2−18+24i+25$
= $16+16i^2$
= $16−16$ $(i^2=−1)$
= 0
= R.H.S
Therefore, -3 + 4i is a solution of the equation $x^2+6x+25=0$.