## Trigonometry (11th Edition) Clone

Since -2 + i satisfies the equation $x^2 + 4x + 5 = 0$, it is a solution of the equation.
For -2 + i to be a solution of the equation $x^2 + 4x + 5 = 0$, -2 + i should satisfy the equation. Substitute $x=-2 + i$ into $x^2 + 4x + 5$, we have $(-2+i)^2 + 4(-2+i) + 5$ = $4 -4i +i^2 -8 + 4i + 5$ = $1 + i^2$ = $1 - 1$ $(i^2 = -1)$ = $0$ = R.H.S Therefore, -2 + i is a solution of the equation $x^2 + 4x + 5 = 0$.