## Trigonometry (11th Edition) Clone

$\theta$ does not exist.
RECALL: The range of the sine functoin $y=\sin{x}$ is $[-1, 1]$. $\theta=\sin^{-1}{2}$ means $\sin{\theta}=2$ Since the range of the sine function is onnly from -1 to 1, then no angle would have a sine value of $2$. Thus, there is no angle $\theta$ such that $\sin{\theta} = 2$.