Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 6 - Inverse Circular Functions and Trigonometric Equations - Section 6.1 Inverse Circular Functions - 6.1 Exercises - Page 264: 16



Work Step by Step

$$y=\arccos 0$$ First, we see that the domain of inverse cosine function is $[-1,1]$. $0$ lies in this range, so $\arccos 0$ exists. Also, it should be noted that the range of inverse cosine function is $[0,\pi]$. In other words, $y\in[0,\pi]$. We can rewrite $y=\arccos 0$ into $\cos y=0$ In the range $[0,\pi]$, we find that only $\cos\frac{\pi}{2}=0$ That means, the exact value of $y$ here is $$y=\frac{\pi}{2}$$
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