Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 96: 62b


$(x_Q,y_Q) = (181.34, 523.02)$

Work Step by Step

From part (a), the equation for $(x_Q,y_Q)$ is: $(x_Q,y_Q) = (x_P+ d~sin~\theta,y_P+ d~cos~\theta)$ We can express the angle $\theta$ in degrees: $\theta = 17^{\circ}19'22''$ $\theta = (17+\frac{19}{60}+\frac{22}{3600})^{\circ}$ $\theta = 17.323^{\circ}$ We can find $x_Q$: $x_Q = x_P+ d~sin~\theta$ $x_Q = (123.62~ft)+ (193.86~ft)~sin~(17.323^{\circ})$ $x_Q = 181.34~ft$ We can find $x_Q$: $y_Q = y_P+ d~cos~\theta$ $y_Q = (337.95~ft)+ (193.86~ft)~cos~(17.323^{\circ})$ $y_Q = 523.02~ft$ $(x_Q,y_Q) = (181.34, 523.02)$
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