#### Answer

Possible solution (wording may differ):
"Find the leg opposite to the angle $25^{o}$ in a right triangle."

#### Work Step by Step

Let an angle in a right triangle be $25^{o}$
Observe TOA in SOHCAHTOA,
Let x be the opposite leg, and y the adjacent.
Then, in that triangle
$\displaystyle \tan 25^{o}=\frac{x}{y}$
when we multiply this with y, we get
$x=y\cdot\tan 25^{o}$, which is of the form given in the problem... (y=3)
So
$x=3\tan 25^{o}$ would be a solution to a problem:
"Find the leg opposite to the angle $25^{o}$ in a right triangle."