## Trigonometry (11th Edition) Clone

1. Name the intersection as point A. At A draw a vertical north/south line and a horizontal east/west line. Place a point B south of A, distance from A = 2(55)=110 miles. 2. Place point C west of of A, such that the bearing from B to C is 32$4^{0}.$ (point C will be $360-324=36^{o}$ west of north, when observing from B) 3. Note that we have a right triangle. Use CAH in SOHCAHTOA. $\displaystyle \cos 36^{o}=\frac{110}{d}$ $d\cos 36^{o}=110$ $d=\displaystyle \frac{110}{\cos 36^{o}}\approx$135.967477525 .