## Trigonometry (11th Edition) Clone

Begin sketching (see below): 1. at point C, draw a vertical north/south line. 2. point B is at an angle of 25$4^{o}$ from north, A is at $344^{o}$ 3. at point B, draw a vertical north/south line. Point A is at $32^{o}$ from north 4. at point A, draw a vertical north/south line. The angle a t A is divided into two 5. Conclude that at C we have a right angle 6. Find the two parts of the angle at A, giving $48^{o}$ Use CAH in SOHCAHTOA. $\displaystyle \cos A=\frac{AC}{AB}\qquad$ (solve for AB) $\displaystyle \cos 48^{\circ}=\frac{780}{AB}$ $AB\cos 48^{\circ}=780$ $AB=\displaystyle \frac{780}{\cos 48^{\circ}}\approx 1165.6917$. The distance from $A$ to $B$ is about 1166 m.