## Trigonometry (11th Edition) Clone

$\tan 60^{\circ}\geq \cot 40^{\circ}$ $\cot 40^{\circ} = \tan (90^{\circ} - 40^{\circ}) = \tan 50^{\circ}$ for $0\leq\theta\leq90^{\circ}$ as angle increase, value of tangent increase , therefore $\tan 60^{\circ}\gt \tan 50^{\circ}$