Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 93: 9



Work Step by Step

$\tan 60^{\circ}\geq \cot 40^{\circ}$ $\cot 40^{\circ} = \tan (90^{\circ} - 40^{\circ}) = \tan 50^{\circ}$ for $0\leq\theta\leq90^{\circ}$ as angle increase, value of tangent increase , therefore $\tan 60^{\circ}\gt \tan 50^{\circ}$
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