Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 93: 4


$\theta = 10^{\circ}$

Work Step by Step

Use the concept of cofunction $\sec x = \csc (90^{\circ} -x)$ $\sec (2\theta +10^{\circ}) = \csc (4\theta +20^{\circ})$ $\sec (2\theta +10^{\circ}) = \sec (90^{\circ} - (4\theta +20^{\circ}))$ $2\theta +10 ^{\circ} = 90^{\circ} -4\theta -20^{\circ}$ $6\theta =60^{\circ}$ $\theta =10^{\circ}$
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