## Trigonometry (11th Edition) Clone

$x = 7^{\circ}$
Use the concept of cofunction $\tan x = \cot (90^{\circ} -x)$ $\tan (5x +11^{\circ}) = \cot (6x +2^{\circ})$ $\tan (5x +11^{\circ}) = \tan (90^{\circ} - (6x +2^{\circ}))$ $5x +11 ^{\circ} = 90^{\circ} -6x -2^{\circ}$ $11x =77^{\circ}$ $x =7^{\circ}$