Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 2 - Review Exercises - Page 93: 2

Answer

$\sin A = \frac{40}{58}$ $\cos A =\frac{42}{58}$ $\tan A = \frac{40}{42}$ $\csc A = \frac{58}{40}$ $\sec A = \frac{58}{42}$ $\cot A = \frac{42}{40}$

Work Step by Step

SOHCAHTOACAO RULE $\sin A = \frac{o}{h} = \frac{40}{58}$ $\cos A = \frac{a}{h} = \frac{42}{58}$ $\tan A = \frac{o}{a} =\frac{40}{42}$ $\csc A = \frac{h}{o} =\frac{58}{40}$ $\sec A = \frac{h}{a} =\frac{58}{42}$ $\cot A = \frac{a}{o} =\frac{42}{40}$
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