Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 28: 30

Answer

$\sin\theta=\frac{y}{r}=\frac{2}{4}=\frac{1}{2}$ $\cos\theta=\frac{x}{r}=\frac{-2\sqrt 3}{4}=-\frac{\sqrt 3}{2}$ $\tan\theta=\frac{y}{x}=\frac{2}{-2\sqrt 3}=-\frac{\sqrt 3}{3}$ $\csc\theta=\frac{r}{y}=\frac{4}{2}=2$ $\sec\theta=\frac{r}{x}=\frac{4}{-2 \sqrt 3}=-\frac{2\sqrt 3}{3}$ $\cot\theta=\frac{x}{y}=\frac{-2\sqrt 3}{2}=-\sqrt 3$

Work Step by Step

$x=-2\sqrt 3$ $y=2$ $r=\sqrt{(-2\sqrt 3)^{2}+(2)^{2}}=\sqrt {12+4}= 4$
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