Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 1 - Trigonometric Functions - Section 1.3 Trigonometric Functions - 1.3 Exercises - Page 28: 14

Answer

$\sin\theta=\frac{y}{r}=\frac{-3}{5}$ $\cos\theta=\frac{x}{r}=\frac{-4}{5}$ $\tan\theta=\frac{y}{x}=\frac{-3}{-4}$ $\csc\theta=\frac{r}{y}=\frac{5}{-3}$ $\sec\theta=\frac{r}{x}=\frac{5}{-4}$ $\cot\theta=\frac{x}{y}=\frac{-4}{-3}$

Work Step by Step

$x=-4$ $y=-3$ $r=\sqrt{(-3)^{2}+(-4)^{2}}=\sqrt {9+16}= 5$
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